CINCINNATI — A member of the Cincinnati Bengals has been named the AFC Offensive Player of the Week for the second week in a row.
[DOWNLOAD: Free WHIO-TV News app for alerts as news breaks]
Wide receiver Tee Higgins earned the honor for his performance against the Tennessee Titans on Sunday, where the Bengals won 43-36 in overtime.
Higgins had 10 catches for 155 yards and two touchdowns.
TRENDING STORIES:
- LIVE ELECTION RESULTS: Nov. 3, 2026 Election
- Browns place Deshaun Watson in concussion protocol
- Police locate suspect vehicle in hit-and-run that killed 14-year-old boy; Investigation ongoing
His 155 receiving yards led all NFL players in Week 8.
This marks the first time Higgins has been named AFC Offensive Player of the Week during his career.
Bengals have held the honors for two weeks now. Quarterback Joe Burrow was the AFC Offensive Player of the Week for Week 7.
[SIGN UP: WHIO-TV Daily Headlines Newsletter]
@2026 Cox Media Group
