log in to manage your profile and account
- Create your account
- Receive up-to-date newsletters
- Set up text alerts
Published: Thursday, March 14, 2019 @ 10:48 PM
By: Dave Jablonski - Staff Writer
BROOKLYN, N.Y. — The third-seeded Dayton Flyers will play No. 6 seed Saint Louis in the quarterfinals of the Atlantic 10 tournament at 8:30 p.m. Friday.
» THREE STORYLINES: What to watch for in Friday’s quarterfinal
The Billikens rallied from an eight-point deficit in the final eight minutes to beat No. 11 seed Richmond 71-68 in the final second-round game at the Barclays Center on Thursday night. Hasahn French led the Billikens (19-12) with 22 points.
Dayton (21-10) split with Saint Louis in the regular losing, losing 73-60 in St. Louis on Feb. 5 and winning 70-62 at UD Arena on Feb. 23.
The Flyers and Billikens haven’t met in the A-10 tournament since 2008 when Dayton won 63-62 at Boardwalk Hall in Atlantic City, N.J.
» PREDICTIONS: What fans expect to see at A-10 tournament
» ARCHDEACON: Toppin’s mom hopes he makes right decision about future
Here are the three other A-10 quarterfinal matchups on Friday. All three games feature teams that split two games in the regular season.
• No. 8 seed Rhode Island beat No. 9 La Salle 76-57 and will play No. 1 Virginia Commonwealth at noon.
• No. 5 George Mason beat No. 12 George Washington 57-51 and will play No. 4 St. Bonaventure at 2:30 p.m.